India beat South Africa by 203 runs in 1st Test 2019, take 1-0 lead in three-match series

While Jadeja took 4 wickets in 2nd innings, Shami managed to scalp 5 wickets in the second innings. Ravichandran Ashwin, who bagged 7 wickets in the first innings, was able to get 1 wicket in the second innings.

Written by October 6, 2019 14:06

New Delhi: India defeated South Africa by 203 runs in the 1st Test in Visakhapatnam. Team India set a massive target of 395 runs for the Proteas in the final innings, which South Africa failed to chase.

While Jadeja took 4 wickets in 2nd innings, Shami managed to scalp 5 wickets in the second innings. Ravichandran Ashwin, who bagged 7 wickets in the first innings, was able to get 1 wicket in the second innings.

R Ashwin and R Jadeja came out as star performers of the match with a total 8 and 6 wickets in the match respectively. South Africa was eventually bowled out for 191.

 

Mayank Agarwal and Rohit Sharma opened the Indian innings and both of them registered a 317-run stand. While Mayank Agarwal (215) smashed a double hundred in his debut match at home, Sharma smashed 176 runs as a Test opener for the first time. In reply, South Africa hit 431 runs in the 1st innings, giving a 71-run lead to India. In the 2nd innings, Sharma fired again and smashed a 127-run knock. He broke multiple records with his innings, taking India to 323-4 in the 2nd innings.

India leads the three-match Test series 1-0. The second Test will commence from October 10 at Maharashtra Cricket Association Stadium in Pune. The T20I series between both the teams had ended in a draw 1-1. With victory in the first match, India have a good chance to clinch the Test series.